(All Steps) The total solar radiation H on a particular surface during an average clear day is given by: H=(5000)/(t^2)+10 where t (-6≤ t≤ 6) is the


Question: The total solar radiation H on a particular surface during an average clear day is given by:

\[H=\frac{5000}{{{t}^{2}}+10}\]

where t ( \[-6\le t\le 6\] ) is the number of hours from noon. Note that 6 a.m. is equivalent to t = -6. Find the instantaneous rate of change of H with respect to t at 3 p.m.

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