(See Solution) The table below describes a probability distribution xj x1=5 x2=15 x3=25 x4=35 x5=45 p(xj) 0.13 0,21 0.34 0.22
Question: The table below describes a probability distribution
xj x1=5 x2=15 x3=25 x4=35 x5=45
p(xj) 0.13 0,21 0.34 0.22 0.1
Deliverable: Word Document 
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