Question: Suppose you throw a baseball straight up at a velocity of 64 feet per second. A function can be created by expressing distance above the ground, s , as a function of time, t . This function is s = -16 t ² + v ₀ t + s ₀

16 represents 1/2g, the gravitational pull due to gravity (measured in feet per second ² ).

v ₀ is the initial velocity (how hard do you throw the object, measured in feet per second).

s ₀ is the initial distance above ground (in feet). If you are standing on the ground, then s ₀ = 0.

1. What is the function that describes this problem?
2. The ball will be how high above the ground after 1 second?
   
3. How long will it take to hit the ground?
4. What is the maximum height of the ball?  What time will the maximum height be attained?

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