(See Steps) y''+y= sin x, y(0)=1, y'(0)=0 y''-y'=xe^x
Question:
- \(y''+y=\sin x,\,\,\,y\left( 0 \right)=1,\,\,y'\left( 0 \right)=0\)
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\(y''-y'=x{{e}^{x}}\) -
\(\left( 1-{{x}^{2}} \right)y''-2xy'+42y=0\)
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Solution: The downloadable solution consists of 5 pages
Deliverable: Word Document 