[See Solution] Solve for X, Y, and Z in the following systems of three equations using either substitution or elimination methods: X + 2Y + Z = 6 X + Y
Question: Solve for X, Y, and Z in the following systems of three equations using either substitution or elimination methods:
-
X + 2Y + Z = 6
X + Y = 4
3X + Y + Z = 8 -
10X + Y + Z = 12
8X + 2Y +Z = 11
20X - 10Y - 2Z = 8 - 22X + 5Y + 7Z = 12
10X + 3Y + 2Z = 5
9X + 2Y + 12Z = 14
Deliverable: Word Document 
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