[Solved] Show that, if EX^2=EY^2=EX Y, then X=Y in MS sense. (Definition: If E(X-Y)^2=0, then we say X=Y in mean square
Question: Show that, if \(E\left\{X^{2}\right\}=E\left\{Y^{2}\right\}=E\{X Y\}\), then \(X=Y\) in MS sense.
(Definition: If \(E\left\{(X-Y)^{2}\right\}=0\), then we say \(X=Y\) in mean square sense.)
Deliverable: Word Document 
Solution: f_x x(x, y)=1 / π, x^2+y^2 ≤q 1; zero, otherwise.
![[See Solution] X and Y have joint](/images/solutions/MC-solution-library-72207.jpg "[See Solution] X and Y have joint density function f_x x(x, y)=lB")
[See Solution] X and Y have joint density function f_x x(x, y)=lB
(Solution Library) Given the joint probability density function
![[Steps Shown] If X_i, i=1,2, ..., n,](/images/solutions/MC-solution-library-72209.jpg "[Steps Shown] If X_i, i=1,2, ..., n, are independent random variables")
[Steps Shown] If X_i, i=1,2, ..., n, are independent random variables
![[Step-by-Step] Under what conditions will the sum](/images/solutions/MC-solution-library-72210.jpg "[Step-by-Step] Under what conditions will the sum of the Mean")
[Step-by-Step] Under what conditions will the sum of the Mean
Operations with Negative Exponents - MathCracker.com