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(See Solution) R is the region that lies between the curve y=(1)/(x^2+4 x+5) and the x -axis from x=-3 to x=-1. Find: the area of R, the volume of the solid

Question: $\mathrm{R}$ is the region that lies between the curve $y=\frac{1}{x^{2}+4 x+5}$ and the $x$ -axis from $x=-3$ to $x=-1$. Find:

the area of $\mathrm{R}$,
the volume of the solid generated by revolving $R$ around the $y$ -axis.
the volume of the solid generated by revolving $\mathrm{R}$ round the $x$ -axis.

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Solution: The downloadable solution consists of 1 pages
Deliverable: Word Document

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(See Solution) R is the region that lies between the curve y=(1)/(x^2+4 x+5) and the x -axis from x=-3 to x=-1. Find: the area of R, the volume of the solid

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