(See Steps) Prove that sin (6theta)=6 sin θ cos θ -32 sin ^3theta cos


Question: Prove that

\[\sin \left( 6\theta \right)=6\sin \theta \cos \theta -32{{\sin }^{3}}\theta {{\cos }^{3}}\theta \]

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Solution: The downloadable solution consists of 1 pages
Deliverable: Word Document

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