Solution: As part of the opening ceremonies for a new skyscraper, a sponge ball is shot off the roof's edge straight into the air, with spectators watching
Question: As part of the opening ceremonies for a new skyscraper, a sponge ball is shot off the roof's edge straight into the air, with spectators watching safely from a distance. The spectator who retrieves the sponge ball will win a cash prize when the streets below the tower are reopened. The following position function describing the height of the sponge ball during its flight:
\[s\left( t \right)=-16{{t}^{2}}+128t+1344\]- From this position function, identify the initial velocity.
- From this position function, identify the height of the office tower.
- What is the height of the sponge ball 3 seconds after it leaves the roof?
- What is the height of the sponge ball 6 seconds after it leaves the roof?
- When does the ball hit the ground? [ COMMENTS & HINTS: What is the height of the sponge ball above the ground when it reaches the ground? Ignore any extraneous or unreasonable answers.]
- When will the sponge ball reach its maximum height above the ground?
- At what height does the ball reach maximum altitude?
- Confirm that the maximum is indeed a maximum two different ways. [ COMMENTS & HINTS: Think analytic geometry and second derivatives.]
- When will the sponge ball pass the edge of the roofline on its descent to the ground? [ COMMENTS & HINTS: Think initial height.]
- What is the velocity of the sponge ball 2 seconds after it leaves the roof?
- What is the velocity of the sponge ball 8 seconds after it leaves the roof?
- What is the velocity of the sponge ball 12 seconds after it leaves the roof?
- What is the velocity of the sponge ball when it reaches the ground?
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