Solution: For any numbers a and b , assume that |a+b|≤ |a|+|b|. Use this to explain that | ∫_R^fdA |≤
Question: For any numbers a and b , assume that \(|a+b|\le |a|+|b|\). Use this to explain that
\[\left| \int\limits_{R}^{{}}{fdA} \right|\le \int\limits_{A}^{{}}{|f|dA}\]
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