(See Solution) Suppose f[x_0, y_0]>f[x, y] for all other x, y near x_0, y_0 . If you center a small circle C at x_0, y_0, why do you expect that the net
Question: Suppose \(f\left[x_{0}, y_{0}\right]>f[x, y]\) for all other \(\{x, y\}\) near \(\left\{x_{0}, y_{0}\right\} .\) If you center a small circle \(C\) at \(\left\{x_{0}, y_{0}\right\}\), why do you expect that the net flow of gradf [x, y] across \(C\) is from outside to inside?
Deliverable: Word Document 
(Steps Shown) Measure by hand calculation the net flow across
(Steps Shown) Here are four vector fields: Field 2[x, y]=y,-x Field 3[x,
![(Step-by-Step) Go with Field [x, y]=-e^x Cos;[y],](/images/solutions/MC-solution-library-71830.jpg "(Step-by-Step) Go with Field [x, y]=-e^x Cos;[y], e^x Sin;[y]")
(Step-by-Step) Go with Field [x, y]=-e^x Cos;[y], e^x Sin;[y]
(Steps Shown) Here's the rectangle R with corners at -2,0,3,0,3,
![[Step-by-Step] You are faced with a hand](/images/solutions/MC-solution-library-71832.jpg "[Step-by-Step] You are faced with a hand calculation of ∫_R")
[Step-by-Step] You are faced with a hand calculation of ∫_R
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