(All Steps) Let z_1,...,z_n and w_1,...,w_n be complex numbers Show that | ∑limits_k=1^nz_kw̄_k |≤ ∑limits_k=1^n|z_k||w_k| If ∑limits_k=1^n|z_k|^2=1


Question: Let \({{z}_{1}},...,{{z}_{n}}\) and \({{w}_{1}},...,{{w}_{n}}\) be complex numbers

  1. Show that
    \[\left| \sum\limits_{k=1}^{n}{{{z}_{k}}{{{\bar{w}}}_{k}}} \right|\le \sum\limits_{k=1}^{n}{|{{z}_{k}}||{{w}_{k}}|}\]
  2. If \(\sum\limits_{k=1}^{n}{|{{z}_{k}}{{|}^{2}}=1}\) and \(\sum\limits_{k=1}^{n}{|{{w}_{k}}{{|}^{2}}=1}\), then show that
    \[\sum\limits_{k=1}^{n}{|{{z}_{k}}{{{\bar{w}}}_{k}}|\,\le \sqrt{\sum\limits_{k=1}^{n}{|{{z}_{k}}{{|}^{2}}}\sum\limits_{k=1}^{n}{|{{w}_{k}}{{|}^{2}}}}}\]
  3. Let \(Z=\left( {{z}_{1}},...,{{z}_{n}} \right)\), and \(W=\left( {{w}_{1}},...,{{w}_{n}} \right)\) be two vectors in \({{\mathbb{C}}^{n}}\). Show that
\[\,\left| \sum\limits_{k=1}^{n}{{{z}_{k}}{{{\bar{w}}}_{k}}} \right|\overset{{}}{\mathop{\le }}\,\sqrt{\sum\limits_{k=1}^{n}{|{{z}_{k}}{{|}^{2}}}\sum\limits_{k=1}^{n}{|{{w}_{k}}{{|}^{2}}}}\]

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Solution: The downloadable solution consists of 3 pages
Deliverable: Word Document

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