[See Solution] Let X̄ be the sample mean of a random sample of size 25 from a gamma distribution with density: f(x)=(1)/(6 β^alpha) x^3 e^-x / β,
Question: Let \(\bar{X}\) be the sample mean of a random sample of size 25 from a gamma distribution with density:
\[f(x)=\frac{1}{6 \beta^{\alpha}} x^{3} e^{-x / \beta}, x>0\]Use the central limit theorem to find an approximate .954 confidence interval for \(\mu=4 \beta\), the mean of this distribution.
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![[Step-by-Step] Let X have a gamma distribution](/images/solutions/MC-solution-library-46337.jpg "[Step-by-Step] Let X have a gamma distribution with α=4 and")
[Step-by-Step] Let X have a gamma distribution with α=4 and
![[Step-by-Step] Given f(x ; θ)=1 / θ,](/images/solutions/MC-solution-library-46338.jpg "[Step-by-Step] Given f(x ; θ)=1 / θ, 00, formally")
[Step-by-Step] Given f(x ; θ)=1 / θ, 00, formally
(Solution Library) Let X ~ Bin;(10, p), p ∈ 1/4, 1/2. The
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(Solution Library) Let X have a Poisson distribution with mean θ.
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