(All Steps) Health insurers and the federal government are both putting pressure on hospitals to shorten the average length of stay (LOS) of their patients.


Question: Health insurers and the federal government are both putting pressure on hospitals to shorten the average length of stay (LOS) of their patients. In 1996, the average LOS for non-heart patient was 4.6 days. A random sample of 20 hospitals in one state had a mean LOS for non-heart patients in 2000 of 3.8 days and a standard deviation of 1.2 days. Calculate a 95% confidence interval for the population mean LOS for non-heart patients in the state’s hospitals in 2000.

  1. [3.24 4.36]
  2. [3.67 3.93]
  3. [3.34 4.26]
  4. [3.38 4.22]
  5. [3.27 4.33]

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Solution: The downloadable solution consists of 1 pages
Deliverable: Word Document

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