[All Steps] Given the probability density function f(x)= (1)/(20)x^3 1≤ x≤ 3 , 0 otherwise
Question: Given the probability density function
\[f\left( x \right)=\left\{ \begin{aligned} & \frac{1}{20}{{x}^{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,1\le x\le 3 \\ & 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{otherwise} \\ \end{aligned} \right.\]- Find the mean
- Find \(p\left( 1.3\le x\le 2.6 \right)\)
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