(See Solution) The given integral is improper both because the interval of integration is unbounded and because the integrand is unbounded near zero. Investigate
Question: The given integral is improper both because the interval of integration is unbounded and because the integrand is unbounded near zero. Investigate its convergence by expressing it as a sum of two integrals-one from 0 to 1 , the other from 1 to \(\infty .\) Evaluate if the integral converge.
\(\int_{0}^{\infty} \frac{1}{x^{2 / 3}+x^{4 / 3}} d x\)
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