Question: Given the following Analysis of Variance Table for three treatments with six

observations each:

Source of

Variation Sum of Squares df Mean Square F value

Treatments 1116

Error 1068

Total 2184

Assume a .05 level of significance. (Show your work, and especially the formulae. You don't have to use Greek Letters, when words will suffice)

1. Find the degrees of freedom (df) for the numerator, denominator and total. (3 points)
2. What is the cutoff (critical) value of F at the 5% level of significance. (State at which point will you reject the null hypothesis?) (2 points)
3. Determine the mean square for treatment and error.
4. Compute the value of F. Do you Reject or Fail to Reject the Null Hypothesis?

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