(Solved) The function A=82.4 e^-0.002 t models the population of Germany, A, in millions, t years after 2006 . What was the population of Germany in $2006
Question: The function
\[A=82.4 e^{-0.002 t}\]models the population of Germany, \(A\), in millions, \(t\) years after 2006 .
- What was the population of Germany in $2006 ?$
- Is the population of Germany increasing or decreasing? Explain.
- In which year will the population of Germany be $81.5$ million?
Deliverable: Word Document 
![[Solution Library] The 1990 population of Europe](/images/solutions/MC-solution-library-65725.jpg "[Solution Library] The 1990 population of Europe was 509 million;")
[Solution Library] The 1990 population of Europe was 509 million;
Solution: Use the exponential decay model, A=A_0 e^k t, to solve
(Solution Library) The logistic growth function f(t)=(140)/(1+9 e^-0.165
![[Solution] Write in exponential form: log _5](/images/solutions/MC-solution-library-65728.jpg "[Solution] Write in exponential form: log _5")
[Solution] Write in exponential form: log _5
(See Solution) Determine whether the values in the table belong
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