(All Steps) Find y' when: y=4x^5-x^2+2x^3/2 y=(x^2-2x)(x^4+5x^2+3)^5 y=(2x^2-5x)/(x^3+2) y=((x)/(x^2-1))^5 y=x^2√5x-1
Question: Find \(y'\) when:
- \(y=4{{x}^{5}}-{{x}^{2}}+2{{x}^{3/2}}\)
- \(y=\left( {{x}^{2}}-2x \right){{\left( {{x}^{4}}+5{{x}^{2}}+3 \right)}^{5}}\)
- \(y=\frac{2{{x}^{2}}-5x}{{{x}^{3}}+2}\)
- \(y={{\left( \frac{x}{{{x}^{2}}-1} \right)}^{5}}\)
- \(y={{x}^{2}}\sqrt{5x-1}\)
- \(y=\frac{{{x}^{3}}-\sqrt{x}}{{{\left( x+3 \right)}^{4}}}\)
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Solution: The downloadable solution consists of 3 pages
Deliverable: Word Document 