[Solved] Find y' when y=1-x^2e^x y=3e^-5x^2+2x y=(e^2x+1)^5 y=5ln 3x y=ln ((x^2+1)/(x+2)) y=8^3x y=x^44^x y=(ln
Question: Find \(y'\) when
- \(y=1-{{x}^{2}}{{e}^{x}}\)
- \(y=3{{e}^{-5{{x}^{2}}+2x}}\)
- \(y={{\left( {{e}^{2x}}+1 \right)}^{5}}\)
- \(y=5\ln 3x\)
- \(y=\ln \left( \frac{{{x}^{2}}+1}{x+2} \right)\)
- \(y={{8}^{3x}}\)
- \(y={{x}^{4}}{{4}^{x}}\)
- \(y=\frac{\ln \left( {{x}^{3}}-4x \right)}{{{3}^{2x-1}}}\)
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