[See] Find the limit. If it doesn’t exist, explain x→ 2lim f(x) where f(x)= x^2-4x+6 x<2 , -x^2+4x-2 x≥ 2
Question: Find the limit. If it doesn’t exist, explain
\[\underset{x\to 2}{\mathop{\lim }}\,f\left( x \right)\]where
\[f\left( x \right)=\left\{ \begin{aligned} & {{x}^{2}}-4x+6\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x<2 \\ & -{{x}^{2}}+4x-2\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x\ge 2 \\ \end{aligned} \right.\]
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