[See Steps] Find an equation for the tangent line to the given curve at the point where x=x_0 . y=(x^2+3 x-1)(2-x) ;


Question: Find an equation for the tangent line to the given curve at the point where \(x={{x}_{0}}\) .

\(y=\left(x^{2}+3 x-1\right)(2-x) ; x_{0}=1\)

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Solution: The downloadable solution consists of 1 pages
Deliverable: Word Document

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