[See Solution] Find the equation of the plane tangent to z=- sin (\Pi y x^2) at the point
Question: Find the equation of the plane tangent to \(z=-\sin \left(\Pi y x^{2}\right)\) at the point \(P=(1,1,0)\)
Deliverable: Word Document 
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Z-test for One Population Proportion - MathCracker.com