[Solution] Find the area of the surface of revolution generated by revolving the given curve around the indicated axis. y=1/5 x^5+(1)/(12 x^3), 1 ≤qq
Question: Find the area of the surface of revolution generated by revolving the given curve around the indicated axis.
\[y=\frac{1}{5} x^{5}+\frac{1}{12 x^{3}}, 1 \leqq x \leqq 2 ;\] the \[y\] -axis
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