[Solution] Explain why the function f(x) = x^2 - 2 if x does not equal -3, 5 if x = -3 f(x)= x^2-2 x≠ -3 , 5 x=3 , is discontinuous at the point x =

Question: Explain why the function f(x) = { x^2 - 2 if x does not equal -3, 5 if x = -3

\[f\left( x \right)=\left\{ \begin{aligned} & {{x}^{2}}-2\,\,\,\,\,\,\,\,\,x\ne -3 \\ & 5\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x=3 \\ \end{aligned} \right.\]

is discontinuous at the point x = -3. Sketch the graph of the function to show the discontinuity at x = -3.

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[Solution] Explain why the function f(x) = x^2 - 2 if x does not equal -3, 5 if x = -3 f(x)= x^2-2 x≠ -3 , 5 x=3 , is discontinuous at the point x =

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