(See Solution) The equation for free fall at the surface of a celestial body in outer space (s in meters, t in seconds) is s = 3.24 t 2 . How long does it take
Question: The equation for free fall at the surface of a celestial body in outer space (s in meters, t in seconds) is s = 3.24 t 2 . How long does it take a rock falling from rest to reach a velocity of 25 m/sec on this celestial body in outer space?
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![[Step-by-Step] Given y=f(u) and u=g(x) , find](/images/solutions/MC-solution-library-43497.jpg "[Step-by-Step] Given y=f(u) and u=g(x) , find (dy)/(dx)=f'(g(x))g'(x)")
[Step-by-Step] Given y=f(u) and u=g(x) , find (dy)/(dx)=f'(g(x))g'(x)
![[Step-by-Step] Write the function in the form](/images/solutions/MC-solution-library-43498.jpg "[Step-by-Step] Write the function in the form y=f(u) and u=g(x) .")
[Step-by-Step] Write the function in the form y=f(u) and u=g(x) .
![[Step-by-Step] Find the derivative of the function](/images/solutions/MC-solution-library-43499.jpg "[Step-by-Step] Find the derivative of the function")
[Step-by-Step] Find the derivative of the function
(See Solution) Find the derivative of the function
![[Solution] Find the first derivative of y=](/images/solutions/MC-solution-library-43501.jpg "[Solution] Find the first derivative of y= sin [ (6t+5)^8/7")
[Solution] Find the first derivative of y= sin [ (6t+5)^8/7
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