(Solution Library) The duration of shoppers' time in Browseworld's new retail outlets is normally distributed with a mean of 41.8 minutes and a standard
Question: The duration of shoppers' time in Browseworld's new retail outlets is normally distributed with a mean of 41.8 minutes and a standard deviation of $17.3$ minutes. How long must a visit be to put a shopper in the longest 20 percent?
Please round your answer to the nearest tenth.
Deliverable: Word Document 
(All Steps) Sales volume last weekend for a sample of ten car dealerships
(Steps Shown) Sales volume last weekend for a sample of ten car
![[Steps Shown] Sales volume last weekend for](/images/solutions/MC-solution-library-70182.jpg "[Steps Shown] Sales volume last weekend for four samples, each")
[Steps Shown] Sales volume last weekend for four samples, each
![[Steps Shown] Sales volume last weekend for](/images/solutions/MC-solution-library-70183.jpg "[Steps Shown] Sales volume last weekend for four samples, each")
[Steps Shown] Sales volume last weekend for four samples, each
![[Solution Library] The mean is 55.3 and](/images/solutions/MC-solution-library-70184.jpg "[Solution Library] The mean is 55.3 and the standard deviation is")
[Solution Library] The mean is 55.3 and the standard deviation is
Bond Value Calculator - MathCracker.com