Solution: The distance in feet traveled by a moving particle traveling over the time interval from t = 1s to t = 4s is given by s=∫_1^5t√26-t^2dt
Question: The distance in feet traveled by a moving particle traveling over the time interval from t = 1s to t = 4s is given by
\[s=\int\limits_{1}^{5}{t\sqrt{26-{{t}^{2}}}dt}\]Evaluate this integral to find s.
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