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(Solution Library) The distance in feet traveled by a car during the first 10 seconds after it starts from rest is given by the formula s(t)=5/2 t^3-4/7 t^7

Question: The distance in feet traveled by a car during the first 10 seconds after it starts from rest is given by the formula $s(t)=\frac{5}{2} t^{3}-\frac{4}{7} t^{7 / 2}$, where $t$ is time in seconds.

What is the velocity (in feet per second) at the end of 1 second?
What is the acceleration (in feet per second $^{2}$ ) at the end of 4 seconds?

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(Solution Library) The distance in feet traveled by a car during the first 10 seconds after it starts from rest is given by the formula s(t)=5/2 t^3-4/7 t^7

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