Question: Consider the right triangle shown in the figure.

1. Show that the area of the triangle is \(A(\alpha)=\frac{1}{2} \int_{0}^{\alpha} \sec ^{2} \theta d \theta\)
2. Show that \(\tan \alpha=\int_{0}^{\alpha} \sec ^{2} \theta d \theta\)
3. Use part (b) to derive the formula for the derivative of the tangent function.

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Solution: The downloadable solution consists of 2 pages
Deliverable: Word Document