(See) Compute the following definite integral using substitution.
Question: Compute the following definite integral using substitution.
\[\int\limits_{0}^{4}{\frac{1}{\sqrt{6t+1}}}dt\]
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![[See Solution] Consider the functions f(x)=-x^2+4 ,](/images/solutions/MC-solution-library-41710.jpg "[See Solution] Consider the functions f(x)=-x^2+4 , g(x)=x^2-2x ,")
[See Solution] Consider the functions f(x)=-x^2+4 , g(x)=x^2-2x ,
![[See Steps] Consider the functions f(x)=x^3-3x^2 ,](/images/solutions/MC-solution-library-41711.jpg "[See Steps] Consider the functions f(x)=x^3-3x^2 , g(x)=x^2+5x")
[See Steps] Consider the functions f(x)=x^3-3x^2 , g(x)=x^2+5x
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