[Solution Library] A bungee jumper leaps from a platform that is 38 metres above a river below. His height above the river is given by: H(t)=20 e^-0.1 t


Question: A bungee jumper leaps from a platform that is 38 metres above a river below. His height above the river is given by:

\[H(t)=20 e^{-0.1 t} \sin \left(t+\frac{\pi}{2}\right)+18\]

where: \(H\) is the height in metres

\(t\) is the time after the jump in seconds

  1. Sketch the graph of the height, \(H\) against the time, \(t\), over the domain [0,40]. (2 marks)
  2. Find the derivative of the function and use this to find the closest distance that the jumper will get to the river. When does this occur? (4 marks)
  3. Find the height of the first upward bounce. When does this occur? ( 3 marks)
  4. How high above the river will the jumper come to rest? (1 mark)

Price: $2.99
Solution: The downloadable solution consists of 2 pages
Deliverable: Word Document

log in to your account

Don't have a membership account?
REGISTER

reset password

Back to
log in

sign up

Back to
log in