[Solution Library] A bungee jumper leaps from a platform that is 38 metres above a river below. His height above the river is given by: H(t)=20 e^-0.1 t
Question: A bungee jumper leaps from a platform that is 38 metres above a river below. His height above the river is given by:
\[H(t)=20 e^{-0.1 t} \sin \left(t+\frac{\pi}{2}\right)+18\]where: \(H\) is the height in metres
\(t\) is the time after the jump in seconds
- Sketch the graph of the height, \(H\) against the time, \(t\), over the domain [0,40]. (2 marks)
- Find the derivative of the function and use this to find the closest distance that the jumper will get to the river. When does this occur? (4 marks)
- Find the height of the first upward bounce. When does this occur? ( 3 marks)
- How high above the river will the jumper come to rest? (1 mark)
Price: $2.99
Solution: The downloadable solution consists of 2 pages
Deliverable: Word Document 