[Solution] A box with a square base and no top is to contain a volume of 48 ft^3. If it costs ,) 3 / ft^2$ for the material for the bottom and ,) 2 / ft^2$
Question: A box with a square base and no top is to contain a volume of \(48 \mathrm{ft}^{3}\). If it costs \(\\) 3 / \mathrm{ft}^{2}$ for the material for the bottom and \(\\) 2 / \mathrm{ft}^{2}$ for the material for the four sides, what should the dimensions of the box be to minimize the total cost of construction? Verify you that you have minimized cost. (12 points)
Deliverable: Word Document 
![[All Steps] A force of 6 pounds](/images/solutions/MC-solution-library-46717.jpg "[All Steps] A force of 6 pounds is required to stretch a spring")
[All Steps] A force of 6 pounds is required to stretch a spring
(See Solution) Let R be the plane region bounded by y=√x, y=6-x,
![[See Steps] If f(x)=x^2 / 3(2 x-5),](/images/solutions/MC-solution-library-46719.jpg "[See Steps] If f(x)=x^2 / 3(2 x-5), then f^prime(x)=(10)/(3) ((x-1))/(x^1")
[See Steps] If f(x)=x^2 / 3(2 x-5), then f^prime(x)=(10)/(3) ((x-1))/(x^1
![[All Steps] Let f(x)=cc[[x-1]] \text if x<0](/images/solutions/MC-solution-library-46720.jpg "[All Steps] Let f(x)=cc[[x-1]] \text if x<0 , x^2-2 \text if 0")
[All Steps] Let f(x)=cc[[x-1]] \text if x<0 , x^2-2 \text if 0
(Step-by-Step) Let f(x)=√4 x+1. Find f^prime(x) using the definition
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