Math Solutions

[See Steps] The average take-out order size for Ashoka Curry House restaurant is shown. Customer order size Statistic Friday night Saturday night Mean order size

Question: The average take-out order size for Ashoka Curry House restaurant is shown.

Customer order size

Statistic Friday night Saturday night

Mean order size 1 = 22.32 2 = 25.56

Standard deviation s 1 = 4.35 s 2 = 6.16

Number of orders n 1 = 13 n 2 = 18

  1. Assuming equal variances, at α = .05, choose the appropriate hypothesis to test for a significant difference in order size between Friday night and Saturday night.
    H 1 : μ 1 ≠ μ 2 versus H 0 : μ 1 = μ 2
    H 0 : μ 1 = μ 2 versus H 1 : μ 1 ≠ μ 2
    b. If t* > 2.045 or t* < – 2.045, you should: Fail to reject the null hypothesis
    Reject the null hypothesis
    c. t* = ___ -1.6232 ______ p-value = ____ 0.1154 ________
    d. What is your decision? Reject the null hypothesis or Fail to reject the null hypothesis
    e. Do you infer that there a significant difference in the order sizes? Yes No
    Price: $2.99
    Solution: The downloadable solution consists of 2 pages
    Deliverable: Word Document


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