Statistics Project

A company supplies pins in bulk to a customer. The company uses an automatic lathe to produce the pins. Due to many causes – vibration, temperature, wear and tear and the like – the lengths of the pins made by the machine are normally distributed with a mean of 1.012 inches and a standard deviation of 0.018 inch. The customer will buy only those pins with lengths in the interval 1.00 plus or minus (+ or -) 0.02 inch. In other words, the customer wants the length to be 1.00 inch but will accept up to 0.02 inch deviation on either side. This 0.02 inch is known as the tolerance.

1. What percentage of the pins will be acceptable to the consumer?

2. If the lathe can be adjusted to have the mean of the lengths to any desired value, what should it be adjusted to? Why?

3. Suppose the mean cannot be adjusted, but the standard deviation can be reduced. What maximum value of the standard deviation would make 90% of the parts acceptable to the consumer? (Assume the mean to be 1.012)

4. Repeat question 3, with 95% and 99% of the pins acceptable.

5. In practice, which one do you think is easier to adjust, the mean or the standard deviation? Why?

6. Assume it costs $150 x² to decrease the standard deviation by (x/1000) inch. Find the cost of reducing the standard deviation to the values found in questions 3 and 4.

7. Now assume that the mean has been adjusted to the best value found in question 2 at a cost of $80. Calculate the reduction in standard deviation necessary to have 90%, 95% and 99% of the parts acceptable. Calculate the respective costs, as in question 6.

8. Based on your answers to questions 6 and 7, what are your recommended mean and standard deviation?

Price: $20.95

Solution: The downloadable solution consists of 5 pages, and 961 words
Deliverable: Word Document and pdf