Part 1 The manufacturer of the X-15 steel-belted radial truck tire claims that the mean mileage the tire
Part 1
The manufacturer of the X-15 steel-belted radial truck tire claims that the mean
mileage the tire can be driven before the tread wears out is 60,000 miles. The
standard deviation of the mileage is 5,000 miles. The Crosset Truck Company
bought 48 tires and found that the mean mileage for their trucks is 59,500
miles. Is Crosset’s experience different from that claimed by the manufacturer
at the 0.05 significance level? Calculation of the p-value is not required.
- Set up the null and alternative hypothesis.
-
Calculate the value of the test statistic.
What is the value of the test statistic? -
What is the decision rule (DR)?
Reject Ho if (complete the DR in next box) - What is your decision regarding Ho?
| Accept or Reject Ho? |
Part 2
The management of White Industries is considering a new method of assembling
its golf cart. The present method requires 42.3 minutes, on the average, to
assemble a cart. The mean assembly time for a random sample of 24 carts, using
the new method, was 40.6 minutes, and the standard deviation of the sample was
2.7 minutes. Using the 0.10 level of significance, can we conclude that the
assembly time using the new method is faster? Calculation of the p-value is not
required.
- Set up the null and alternative hypothesis.
-
Calculate the value of the test statistic.
What is the value of the test statistic? -
What is the decision rule (DR)?
Reject Ho if (complete the DR in next box) - What is your decision regarding Ho?
| Accept or Reject Ho? |
Part 3 .
A recent study focused on the number of times men and women who live alone buy takeout dinner in a month. The information is summarized below.
| Statistic | Men | Women |
| Mean | 24.51 | 22.69 |
| Standard deviation | 4.48 | 3.86 |
| Sample size | 35 | 40 |
At the 0.01 significance level, is there a difference in the mean number of times men and women order takeout dinners in a month? Calculation of the p-value is not required.
- Set up the null and alternative hypothesis.
-
Calculate the value of the test statistic.
What is the value of the test statistic? -
What is the decision rule (DR)?
Reject Ho if (complete the DR in next box) - What is your decision regarding Ho?
| Accept or Reject Ho? |
Part 4
The production manager at Bellevue Steel, a manufacturer of wheelchairs, wants to compare the number of defective wheelchairs produced on the day shift with the number on the afternoon shift. A sample of the production from 6 day shifts and 8 afternoon shifts revealed the following number of defects. Assume this is a two sample "Unknown Variances, Assumed Equal". The level of significance is 0.05. The standard deviation for Day is 1.4142 and the standard deviation for Afternoon is 2.2678.
| Day | 5 | 8 | 7 | 6 | 9 | 7 | ||
| Afternoon | 8 | 10 | 7 | 11 | 9 | 12 | 14 | 9 |
- Set up the null and alternative hypothesis.
-
Calculate the value of the test statistic.
Note: if you use manual or Megastat, select Hypothesis Test: Independent Groups (t test, pooled variance)What is the value of the test statistic? -
What is the decision rule (DR)?
Reject Ho if (complete the DR in next box) - What is your decision regarding Ho?
| Accept or Reject Ho? |
Deliverable: Word Document
