[Solution] Find the equation of the plane tangent to z=- sin (π yx^2) at the point
Question: Find the equation of the plane tangent to \(z=-\sin \left( \pi y{{x}^{2}} \right)\) at the point \(P=(1,1,0)\)
Deliverable: Word Document 
![[See Steps] A box with its base](/images/solutions/MC-solution-library-35405.jpg "[See Steps] A box with its base in the xy-plane has its four upper")
[See Steps] A box with its base in the xy-plane has its four upper
![[All Steps] Find the differential $d w$](/images/solutions/MC-solution-library-35406.jpg "[All Steps] Find the differential $d w$ for w=y sin")
[All Steps] Find the differential $d w$ for w=y sin
(Solution Library) Find (∂ r)/(∂ x), (∂ r)/(∂ y),
![[All Steps] Given f(x, y, z)=\mathrmx^2 \mathrmy^3](/images/solutions/MC-solution-library-35408.jpg "[All Steps] Given f(x, y, z)=\mathrmx^2 \mathrmy^3 z^6, in what")
[All Steps] Given f(x, y, z)=\mathrmx^2 \mathrmy^3 z^6, in what
(See) The plane 2 y+4 z=5 meets the cone z^2=4(\mathrmx^2+\mathrmy^2)
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